A) \[1:1\]
B) \[81/16\]
C) \[36/81\]
D) \[8/17\]
Correct Answer: A
Solution :
As, \[\frac{{{\lambda }_{1}}}{{{\lambda }_{2}}}=\frac{{{T}_{1}}}{{{T}_{2}}}=\frac{3}{2}\] \[\Rightarrow \] \[{{\left( \frac{{{T}_{1}}}{{{T}_{2}}} \right)}^{4}}=\frac{81}{16}\] and \[\frac{{{A}_{1}}}{{{A}_{2}}}={{\left[ \frac{{{r}_{1}}}{{{r}_{2}}} \right]}^{2}}=\frac{16}{81}\] also \[{{E}_{1}}=e\sigma A{{T}^{4}}\] \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{1}{1}=1:1\]
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