A) \[{{H}_{3}}C-C{{H}_{2}}OH+{{C}_{6}}{{H}_{6}}\]
B) \[C{{H}_{3}}-CH=C{{H}_{2}}+{{C}_{6}}{{H}_{6}}\]
C) \[{{H}_{2}}C=C{{H}_{2}}+{{C}_{6}}{{H}_{6}}\]
D) \[{{H}_{3}}C=C{{H}_{2}}+{{C}_{6}}{{H}_{6}}\]
Correct Answer: C
Solution :
\[{{C}_{6}}{{H}_{6}}+C{{H}_{2}}=C{{H}_{2}}\xrightarrow{AlC{{l}_{3}}}{{C}_{6}}{{H}_{5}}C{{H}_{2}}C{{H}_{3}}\]
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