A) depends on v and not on R
B) depends on both R and v
C) is independent of both R and v
D) depends on R and not on v
Correct Answer: C
Solution :
To move on circular path in a magnetic field, a centripetal force is provided by the magnetic force. When magnetic field is perpendicular to motion of charged particle, then Centripetal force = magnetic force That is \[\frac{m{{v}^{2}}}{R}=Bqv\]or \[R=\frac{mv}{Bq}\] Further, time period of the motion \[T=\frac{2\pi R}{v}=\frac{2\pi \left( \frac{mv}{Bq} \right)}{v}\]or \[T=\frac{2\pi m}{Bq}\] It is independent of both R and v.
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