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NEET Sample Paper NEET Sample Test Paper-25

  • question_answer
    Two points are located at a distance of 10 m and 15 m from the source of oscillation. The period of oscillation is 0.05 s and the velocity of the wave is 300 m/s. What is the phase difference between the oscillations of two points?

    A) \[\frac{\pi }{3}\]

    B) \[\frac{2\pi }{3}\]

    C) \[\pi \]

    D)  \[\frac{\pi }{6}\]

    Correct Answer: B

    Solution :

     Phase difference\[=\frac{2\pi }{\lambda }\times \]path difference Path difference between two points, \[\Delta x=15-10=5\,m\] The period, \[T=0.05\,s\] \[\Rightarrow \]Frequency \[v=\frac{1}{T}=\frac{1}{0.05}=20\,Hz\] Velocity, \[v=300\,m/s\] \[\therefore \]      Wavelength, \[\lambda =\frac{v}{v}=\frac{300}{20}=15\,m\] Hence, phase difference \[\Delta \phi =\frac{2\pi }{\lambda }\times \Delta x=\frac{2\pi }{15}\times 5=\frac{2\pi }{3}\]


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