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NEET Sample Paper NEET Sample Test Paper-24

  • question_answer
    The displacement of a particle is given by \[y=a+bt+c{{t}^{2}}-d{{t}^{4}}.\]The initial velocity and acceleration are respectively

    A) \[b,-4d\]            

    B) \[-b,2c\]

    C) \[b,2c\]                         

    D) \[2c,-4d\]

    Correct Answer: C

    Solution :

     \[y=a+bt+c{{t}^{2}}-d{{t}^{4}}\] \[\therefore \]\[v=\frac{dv}{dt}=b+2ct-4d{{t}^{3}}\] and \[a=\frac{dv}{dt}=2c-12\,d{{t}^{2}}\] Hence, at t = 0, \[{{v}_{initial}}=b\]and \[{{a}_{initial}}=2c.\]


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