A) Treating ethanol over heated alumina.
B) Heating sodium ethoxie with ethyl bromide.
C) Heating ethanol with dry \[A{{g}_{2}}O.\]
D) Treating ethyl alcohol with excess of \[{{H}_{2}}S{{O}_{4}}\]at 430 to 44 K.
Correct Answer: B
Solution :
\[\underset{\text{Sodium}\,\text{ethoxide}}{\mathop{\text{C}{{\text{H}}_{\text{3}}}\text{C}{{\text{H}}_{\text{2}}}\text{ONa}}}\,\text{+}\underset{\text{Bromo}\,\text{Ethane}}{\mathop{{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{5}}}\text{Br}}}\,\xrightarrow[\text{Synthesis}]{\text{William }\!\!'\!\!\text{ s}}\]\[\underset{\text{Ethoxyethane}}{\mathop{C{{H}_{3}}C{{H}_{2}}OC{{H}_{2}}C{{H}_{3}}}}\,+NaBr\] Hence, the correct option is [b].
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