A) 400.0 Hz to 484.0 Hz
B) 403.3 Hz to 480.0 Hz
C) 400.0 Hz to 480.0 Hz
D) 403.3 Hz to 484.0 Hz
Correct Answer: D
Solution :
\[{{f}_{\max }}=\frac{v}{v-{{v}_{s}}}\times {{f}_{0}};\]where, \[{{f}_{0}}=440\,Hz\] Here,\[v=330m/s,\,{{v}_{s}}=r\omega =1.5\times 20=30\,m/s\] Inserting the above values, we get \[{{f}_{\max }}=\frac{330}{330-30}\times 440=484\,Hz\] \[{{f}_{\min }}=\frac{330\times 440}{330-(-30)}=403\,.3Hz\] Hence, the correction option is [d].You need to login to perform this action.
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