A) \[1\,\overset{\text{o}}{\mathop{\text{A}}}\,\]
B) \[{{10}^{-10\text{ }}}cm\]
C) \[~{{10}^{-12}}\text{ }cm\]
D) \[~{{10}^{-15}}\text{ }cm\]
Correct Answer: C
Solution :
The distance of closet approach is given by \[{{r}_{0}}=\frac{1}{4\pi {{\varepsilon }_{0}}}.\frac{2Z{{e}^{2}}}{{{E}_{k}}}.\]Here, \[Z=92\]and \[{{E}_{k}}=5\,MeV\] Putting the values, we get\[{{r}_{0}}={{10}^{-12}}\,cm.\] Hence, the correction option is [c].
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