A) \[{{C}_{2}}{{H}_{4}}\]
B) \[C{{H}_{3}}C{{H}_{2}}OH\]
C) \[C{{H}_{3}}Br\]
D) \[C{{H}_{3}}O\]
Correct Answer: C
Solution :
\[C{{H}_{3}}B{{r}_{2}}+{{H}_{2}}\xrightarrow{LiAl{{H}_{4}}}\underset{\text{Methane}}{\mathop{C{{H}_{4}}}}\,\] \[\xrightarrow{Na}\underset{\text{Ethane}}{\mathop{C{{H}_{3}}-C{{H}_{3}}}}\,\] Hence, the correct option is (c).
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