A) \[~10\times {{10}^{23}}\]
B) \[~35\times {{10}^{23}}\]
C) \[~28\times {{10}^{23}}\]
D) \[~48\times {{10}^{23}}\]
Correct Answer: D
Solution :
As we know that four sodium atom are present in sodium Ferro cyanide \[[N{{a}_{4}}(Fe{{(CN)}_{6}}].\] Hence, number of Na atoms = Number of moles\[\times \]Number of atoms\[\times \]Avogadro's number \[=2\times 4\times 6.023\times {{10}^{23}}=48\times {{10}^{23}}\] Hence, the correct option is (d).
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