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NEET Sample Paper NEET Sample Test Paper-22

  • question_answer
    The radius of second orbit of an electron in hydrogen atom is 2. 116 A. The de-Broglie wavelength associated with this electron in this orbit would be:

    A) \[6.64\text{ }\overset{\text{o}}{\mathop{\text{A}}}\,\]             

    B)      \[~1.058\text{ }\overset{\text{o}}{\mathop{\text{A}}}\,\]  

    C)      \[2.116\text{ }\overset{\text{o}}{\mathop{\text{A}}}\,\]            

    D)      \[~13,28\text{ }\overset{\text{o}}{\mathop{\text{A}}}\,\]

    Correct Answer: A

    Solution :

    \[mvr=n\frac{h}{2\pi }=2\left( \frac{h}{2\pi } \right)\]or \[mvr=\frac{h}{\pi }\] \[\therefore \]\[\frac{h}{mv}=de-\]Broglie wavelength \[=\pi r\] \[=(3.14)(2.116\overset{\text{o}}{\mathop{A}}\,)=6.64\overset{\text{o}}{\mathop{A}}\,\] Hence, the correction option is [a].


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