A) 10 cm/s
B) 15 cm/s
C) 20 cm/s
D) 40 cm/s
Correct Answer: C
Solution :
According to the problem \[8\times \frac{4}{3}\pi {{r}^{3}}=\frac{4}{3}\pi {{R}^{3}}\]or \[R=2r\] Now, \[{{v}_{1}}\propto {{r}^{2}}\] Since the radius becomes twice, \[\therefore \]The terminal velocity becomes 4 times or 20 m/s. Hence, the correction option is [c].
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