A) \[\frac{1}{e}\]
B) \[1-\frac{1}{e}\]
C) \[\frac{\ln \,2}{3}\]
D) \[1-\frac{\ln \,2}{e}\]
Correct Answer: A
Solution :
\[{{P}_{(survival)}}=\frac{N(t)}{{{N}_{0}}}=\frac{{{N}_{0}}{{e}^{-\lambda t}}}{{{N}_{0}}}={{e}^{-\lambda t}}\] For \[t=\frac{1}{\lambda },{{P}_{(survival)}}=\frac{1}{e}\] Hence, the correction option is [a].
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