A) \[{{H}_{2}}\]
B) \[{{F}_{2}}\]
C) \[{{O}_{2}}\]
D) \[{{N}_{2}}\]
Correct Answer: B
Solution :
In \[{{F}_{2}},\]the bond energy is less due to greater inter- electronic repulsions. Hence, the correct option is (b).
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