A) \[T{{i}^{4+}}\]
B) \[Z{{n}^{2+}}\]
C) \[N{{i}^{2+}}\]
D) \[S{{c}^{3+}}\]
Correct Answer: C
Solution :
\[T{{i}^{4+}},Z{{n}^{2+}},S{{c}^{3+}}\]are not carrying unpaired electrons. But\[N{{i}^{2+}}\]with \[{{d}^{8}},\]electronic configuration carry two unpaired electrons. So it is colored. Hence, the correct option is (c).
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