A) \[C{{H}_{3}}CHO\]
B) \[{{C}_{2}}{{H}_{5}}O{{C}_{2}}{{H}_{5}}\]
C) \[{{C}_{2}}{{H}_{5}}ONa\]
D) \[C{{H}_{3}}COOH\]
Correct Answer: C
Solution :
\[C{{H}_{3}}-C{{H}_{2}}Cl+\underset{(Y)}{\mathop{{{C}_{2}}{{H}_{5}}ONa}}\,\to \underset{(Z)}{\mathop{{{C}_{2}}{{H}_{5}}O{{C}_{2}}{{H}_{5}}+}}\,\] \[NaCl\xrightarrow{2HI}C{{H}_{3}}-C{{H}_{2}}-I+{{H}_{2}}O\] Hence, the correct option is (a).
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