A) \[2KI+{{H}_{2}}{{O}_{2}}+{{H}_{2}}S{{O}_{4}}\to {{K}_{2}}S{{O}_{4}}+{{I}_{2}}+{{H}_{2}}O\]
B) \[A{{g}_{2}}O(moist)+{{H}_{2}}{{O}_{2}}\to 2Ag+{{H}_{2}}O+{{O}_{2}}\]
C) \[N{{a}_{2}}S{{O}_{3}}+{{H}_{2}}{{O}_{2}}\to N{{a}_{2}}S{{O}_{4}}+{{H}_{2}}O\]
D) \[PbS+4{{H}_{2}}{{O}_{2}}\to PbS{{O}_{4}}+4{{H}_{2}}O\]
Correct Answer: B
Solution :
\[A{{g}_{2}}O+{{H}_{2}}{{O}_{2}}\to 2Ag+{{H}_{2}}O+{{O}_{2}}\] Here\[{{H}_{2}}{{O}_{2}}\]reduces \[A{{g}_{2}}O\]into Ag while in all other cases \[{{H}_{2}}{{O}_{2}}\]acts as an oxidant. Hence, the correct option is (b).
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