2. Sample Papers
  3. NEET

NEET Sample Paper NEET Sample Test Paper-21

  • question_answer
    A speech signal of 3 kHz is used to modulate a carrier signal of frequency 1 MHz, using amplitude modulation. The frequencies of the side bands will be

    A)  1.003 MHz and 0.997 MHz

    B)  3001 kHz and 2997 kHz

    C)  1003 kHz and 1000 kHz

    D)  1 MHz and 0.997 MHz

    Correct Answer: A

    Solution :

    Here, \[\upsilon =1\,MHz,\,\Delta v=3\,kHz=0.003\,MHz.\] Using amplitude modulation, the frequencies of the side band \[=(\upsilon +\Delta v)\]and \[(\upsilon -\Delta v)\] \[=(1+0.003)\]and \[(1-0.003)\] \[=1.003\,MHz\]and 0.997 MHz Hence, the correction option is (a).


You need to login to perform this action.
You will be redirected in 3 sec spinner