A) \[{{x}^{2}}\]
B) \[{{e}^{x}}\]
C) \[x\]
D) \[{{\log }_{e}}x\]
Correct Answer: A
Solution :
The given condition is that of simple harmonic motion. As the particle moves from mean position to any other position, its potential energy increases by \[\frac{1}{2}K{{x}^{2}},\] so in conformance with mechanical energy conservation its kinetic energy must decrease by \[\frac{1}{2}K{{x}^{2}}.\] Hence, the correction option is (a).
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