• # question_answer Find the force needed to hold the wedge in equilibrium, if there is no friction A) $\frac{mg}{\cos \theta }$                  B) $mg\,\sin \theta$        C)    $mg{{\sin }^{2}}\theta$   D)   $mg\cos \theta \sin \theta$

For the block, $N=mg\cos \theta$ For the horizontal equilibrium of the wedge, $F=N\sin \theta$ $\therefore$$F=mg\cos \theta \sin \theta$ Hence, the correction option is (d).