A) 50
B) 5
C) 500
D) More than 5 million
Correct Answer: B
Solution :
Let n be the number of photons falling per second on the retina, then, \[nhv\] \[=1.7\times {{10}^{-18}}\] or \[\frac{nhc}{\lambda }=1.7\times {{10}^{-18}},\]or \[n=\frac{1.7\times {{10}^{-18}}\lambda }{hc}\] \[\therefore \]\[n=\frac{1.7\times {{10}^{-18}}\times 6000\times {{10}^{10}}}{6.6\times {{10}^{-34}}\times 3\times {{10}^{-8}}}=5.15=5.\] Hence, the correction option is (b).
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