A) 1.0 m/s
B) 0.5 m/s
C) 1.5 m/s
D) 2.0 m/s
Correct Answer: A
Solution :
Kinetic energy of rotating body \[=\frac{1}{2}I{{\omega }^{2}}=\frac{1}{2}\times 3\times {{3}^{2}}=13.5\,J\] Kinetic energy of translating body \[=\frac{1}{2}m{{u}^{2}}\] \[\therefore \]\[\frac{1}{2}m{{u}^{2}}=13.5\]or \[\frac{1}{2}\times 27{{u}^{2}}=13.5\]or \[u=1\,m/s.\]You need to login to perform this action.
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