NEET Sample Paper NEET Sample Test Paper-21

  • question_answer An induction coil has an impedance of \[10\Omega .\]When an AC signal of frequency 1000 Hz is applied to the coil, the voltage leads the current by \[45{}^\circ \]. The inductance of the coil is

    A)  \[\frac{1}{20\pi }\]    

    B)   \[\frac{1}{\sqrt{2}\times 200\pi }\]    

    C)    \[\frac{1}{\sqrt{2}\times 20\pi }\]     

    D)   \[\frac{1}{200\pi }\]   

    Correct Answer: B

    Solution :

    \[\text{Tan}\,{{45}^{o}}=\frac{\omega L}{R}\Rightarrow L=R\] Also, \[Z=\sqrt{{{R}^{2}}+{{(\omega L)}^{2}}}=10\] \[\therefore \]\[L=\frac{5\sqrt{2}}{2\pi \times 1000}=\frac{1}{\sqrt{2}\times 200\pi }H\]             Hence, the correction option is(b).

adversite


You need to login to perform this action.
You will be redirected in 3 sec spinner