• question_answer Parallel plate condenser with oil between the plates (dielectric constant of oil $K=2$) has a capacitance C. if the oil is removed then capacitance of the capacitor becomes: A)  $\frac{C}{2}$                 B)  $\frac{C}{\sqrt{2}}$C)  $2C$                         D)  $\sqrt{2}C$

Dielectric constant of oil $k=2.$ Capacitance of the capacitor with oil, ${{C}_{m}}=C$ The capacitance of the conductor with oil              ${{C}_{m}}=K{{C}_{o}}$ $\Rightarrow$               $C=2\times {{C}_{o}}$ (Where ${{C}_{o}}$ is the capacitance of the capacitor after oil is removed)