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NEET Sample Paper NEET Sample Test Paper-1

  • question_answer
    The vapour pressure of pure liquid solvent A is \[0.80\] atm. When a non-volatile substance B is added to the solvent, its vapour pressure drops to \[0.60\]atm. What is the mole fraction of component B is the solution?

    A)  \[0.75\]                       

    B)  \[0.25\]

    C)  \[0.40\]                       

    D)  \[0.60\]

    Correct Answer: B

    Solution :

    \[P={{X}_{A}}{{P}^{o}}\] \[{{X}_{A}}=\frac{P}{{{P}^{o}}}=\frac{0.60\,atm}{0.80\,atm}=0.75\] \[{{X}_{B}}=1-0.75=0.25\]


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