• # question_answer $7\mu f$capacitor is charged by a 50V battery. Plow much electrostatic energy is stored by it? A)  $1.7\times {{10}^{-8}}J$              B)  $13.6\times {{10}^{-9}}J$C)  $8.75\times {{10}^{-3}}J$       D)  $6.7\times {{10}^{-7}}J$

Solution :

Here,    $C=7\mu F=7\times {{10}^{-6}}F.$ $V=50$ volt $\therefore$ Energy stored $=\frac{1}{2}C{{V}^{2}}$ $=\frac{1}{2}\times 7\times {{10}^{-6}}\times {{(50)}^{2}}$ $=8.75\times {{10}^{-3}}J$

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