A) \[Ni\]
B) \[Cr\]
C) \[Sn\]
D) \[Pb\]
Correct Answer: A
Solution :
\[Ni\] combines with \[CO\] at \[323\text{ }K\] to form \[Ni\,{{(CO)}_{4}}\]which decomposes thermally at \[423\,K\] to give pure \[Ni\] metal. \[Ni{{(CO)}_{4}}\xrightarrow{423\,K}Ni+4CO\uparrow \]
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