• # question_answer Solute A is a ternary electrolyte and solute B is a non-eletrolyte. If $0.1\text{ }M$ solution of solute B produces an osmotic pressure of 2P, then $0.05\text{ }M$solution of A at the same temperature will produce an osmotic pressure equal to A)  $1.5\,P$                    B)  $2\,P$C)  $3\,P$                       D)  P

$0.05\text{ }M$ solution of $A=3\times 0.05\,M$ ion = $0.15\text{ }M$ ions $0.1\text{ }M$ solution of B (non-electrolyte) has osmotic pressure $=2P$ $\therefore$ $0.15\text{ }M$ solution will have osmotic pressure$=\frac{2P}{0.1}\times 0.15=3P$