A) \[1.7\times {{10}^{-8}}J\]
B) \[13.6\times {{10}^{-9}}J\]
C) \[8.75\times {{10}^{-3}}J\]
D) \[6.7\times {{10}^{-7}}J\]
Correct Answer: C
Solution :
Here, \[C=7\mu F=7\times {{10}^{-6}}F.\] \[V=50\] volt \[\therefore \] Energy stored \[=\frac{1}{2}C{{V}^{2}}\] \[=\frac{1}{2}\times 7\times {{10}^{-6}}\times {{(50)}^{2}}\] \[=8.75\times {{10}^{-3}}J\]
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