A) \[5.2\times {{10}^{3}}N\]
B) \[4.2\times {{10}^{3}}N\]
C) \[3.2\times {{10}^{3}}N\]
D) \[2.2\times {{10}^{3}}N\]
Correct Answer: A
Solution :
Here mass of the bullet \[=20g=0.02\,kg\] Speed \[\upsilon =250\,m/s\]. Distance \[s=12\,cm=0.12\,m\] \[\therefore \] Loss of kinetic energy \[=\frac{1}{2}\,m{{\upsilon }^{2}}\] \[=\frac{1}{2}\times 0.02\times {{(250)}^{2}}\] \[=625\,J\] Now from energy theorem, we have \[F\times 0.12=625\] \[\Rightarrow \] \[F=\frac{625}{0.12}\] \[\Rightarrow \] \[F=5.2\times {{10}^{3}}N\]
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