• question_answer 56) The hybrid state of $Co$ in high spin ${{K}_{3}}Co{{F}_{6}}$ complex is A)  $s{{p}^{3}}{{d}^{2}}$          B)  $s{{p}^{3}}$C)  ${{d}^{2}}s{{p}^{3}}$                         D)  $s{{p}^{3}}d$

In ${{K}_{4}}Co{{F}_{a}}$ the hybrid state of $Co$ is $s{{p}^{3}}{{d}^{2}}$ giving a high spin complex.