A) \[{{H}_{2}}O,\,{{H}_{2}}S,\,{{H}_{2}}Se,\,{{H}_{2}}Te\]
B) \[{{H}_{2}}Te,{{H}_{2}}Se,\,{{H}_{2}}S,\,{{H}_{2}}O\]
C) \[{{H}_{2}}S,{{H}_{2}}O,{{H}_{2}}Se,\,\,{{H}_{2}}Te\]
D) \[{{H}_{2}}Se,\,{{H}_{2}}S,{{H}_{2}}O,\,{{H}_{2}}Te\]
Correct Answer: B
Solution :
As the size of the central atom M in \[{{H}_{2}}M\] increases from O to \[Te,\]the H-M bond becomes weaker and breaks easily on heating. Hence, \[{{H}_{2}}O\] is most stable and \[{{H}_{2}}Te\]is least stable.
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