A) \[{{0.19}^{o}}C\]
B) \[{{0.24}^{o}}C\]
C) \[{{0.40}^{o}}C\]
D) \[{{1.16}^{o}}C\]
Correct Answer: D
Solution :
Height of waterfall \[h=500\,m\] Specific heat of water \[s=4200\,J/k{{g}^{o}}C\] The potential energy of water \[=mgh\] \[=m\times 9.8\times 500\] \[=4900\,m\] ??.(i) Increase in heat energy \[=ms\,\theta =4200\,m\,\theta \] ?...(ii) (Where \[\theta \] is the rise in temperature) As the entire potential energy of water is converted into heat energy. Hence, equating both the energies from (i) and (u), we get \[4900\,m=4200\,m\theta .\] \[\Rightarrow \] \[\theta =\frac{4900}{4200}={{1.16}^{o}}C\]
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