A) \[\frac{1}{3680}\]
B) \[\frac{1}{4680}\]
C) \[\frac{1}{5680}\]
D) none of these
Correct Answer: A
Solution :
Ratio, \[R=\frac{\left( \frac{e}{m} \right)\alpha }{\left( \frac{e}{m} \right)electron}=\frac{\frac{2e}{4{{m}_{p}}}}{\frac{e}{{{m}_{e}}}}\] Where \[m & p\] is mass of proton and \[{{m}_{e}}\] is mass of electron. \[\therefore \] \[R=\frac{{{m}_{e}}}{2{{m}_{p}}}\] \[=\frac{{{m}_{e}}}{2\times 1840{{m}_{e}}}\] \[[\because {{m}_{p}}=1840\,{{m}_{e}}]\] \[=\frac{1}{3680}\]
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