2. Sample Papers
  3. NEET

NEET Sample Paper NEET Sample Test Paper-1

  • question_answer
    In a coil having emf of 8 volt is induced for \[0.05\] the value of current changes from 2amp to 4amp. What will be the value of coefficient of self induction of the coil?

    A)  \[0.8\] henry               

    B)  \[0.4\] henry

    C)  \[0.2\] henry               

    D)  none of these

    Correct Answer: C

    Solution :

    Here: Emf \[E=8\]volt Time \[t=0.05\text{ }sec\]. initial current \[{{i}_{1}}=2\] amp \[\Rightarrow \] final current \[{{i}_{2}}=4\] amp From the Faraday's law of electromagnetic induction, the induced emf is given by                         \[E=-L\frac{di}{dt}\]                 \[\Rightarrow \]               \[S=-L\,\frac{di}{dt}\]                 \[\Rightarrow \]               \[L=-8\frac{dt}{di}=-8\frac{dt}{({{i}_{1}}-{{i}_{2}})}\] \[=-8\times \frac{0.05}{2-4}=0.2\] henry.


You need to login to perform this action.
You will be redirected in 3 sec spinner