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NEET Sample Paper NEET Sample Test Paper-1

  • question_answer
    The kinetic energy of one gramme molecule of a gas, at normal temperature and pressure will be \[(R=8.31\,J\,mole\,K)\]:

    A)  \[3.4\times {{10}^{3}}J\]         

    B)  \[2.7\times {{10}^{2}}J\]

    C)  \[1.2\times {{10}^{2}}J\]          

    D)  none of these

    Correct Answer: A

    Solution :

    We know that the kinetic energy of \[1g\] molecule of an ideal gas is \[E=\frac{3}{2}\,RT\] Here     \[R=8.31\,J/mol\,K\]   and        \[~T={{273}^{o}}K\] \[\therefore \]  \[E=\frac{3}{2}\times 8.31\times 273=3.4\times {{10}^{3}}J\]


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