NEET Sample Paper NEET Sample Test Paper-1

  • question_answer Electron beam is allowed to pass normally through mutually perpendicular magnetic electric fields. If magnetic field induction and electric field strength are \[0.0004\text{ }Wb/{{m}^{2}}\] and \[3000\text{ }V/m\] respectively and beam suffers no deflection. Then the velocity of electron will be:

    A) \[1.2\times {{10}^{6}}\text{ }m/s\]

    B)  \[7.5\times {{10}^{12}}\text{ }m/s\]

    C)  \[7.5\times {{10}^{6}}\text{ }m/s\]       

    D)  none of these

    Correct Answer: C

    Solution :

    Here, magnetic field \[B=0.0004\text{ }Wb/{{m}^{2}}.\] Electric field       \[E=3000\text{ }V/m.\] The velocity of an electron, when beam suffers no deflection is given by                         \[V=\frac{E}{B}\]                                 \[=\frac{3000}{0.0004}=7.5\times {{10}^{6}}\,m/s\]


You need to login to perform this action.
You will be redirected in 3 sec spinner