• # question_answer 16) Radius of the circular path of and electron subjected to a perpendicular magnetic field is: A)  $\frac{mV}{Be}$       B)  $\frac{me}{B}$C)  $\frac{mE}{B}$                                             D)  none of these

Solution :

As the centripetal force on an electron is $=\frac{m\,{{V}^{2}}}{r}$                                  ?..(i) (where r is the radius of circular path) and force on a moving charge in the magnetic field is $=BeV$                 ......(ii) Equating (i) and (ii), we get.             $\frac{m{{V}^{2}}}{r}=BeV$ $\Rightarrow$               $r=\frac{mV}{Be}$

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