NEET Sample Paper NEET Sample Test Paper-1

  • question_answer Radius of the circular path of and electron subjected to a perpendicular magnetic field is:

    A)  \[\frac{mV}{Be}\]       

    B)  \[\frac{me}{B}\]

    C)  \[\frac{mE}{B}\]                                             

    D)  none of these

    Correct Answer: A

    Solution :

    As the centripetal force on an electron is \[=\frac{m\,{{V}^{2}}}{r}\]                                  ?..(i) (where r is the radius of circular path) and force on a moving charge in the magnetic field is \[=BeV\]                 ......(ii) Equating (i) and (ii), we get.             \[\frac{m{{V}^{2}}}{r}=BeV\] \[\Rightarrow \]               \[r=\frac{mV}{Be}\]       


You need to login to perform this action.
You will be redirected in 3 sec spinner