NEET Sample Paper NEET Sample Test Paper-19

  • question_answer A compound has C = 40%, H =13.33% and N = 46.67. The empirical formula is

    A) \[C{{H}_{4}}N\]                  

    B) \[C{{H}_{4}}{{H}_{4}}\]

    C) \[C{{H}_{2}}N\]                  

    D) \[{{C}_{2}}{{H}_{5}}N\]   

    Correct Answer: A

    Solution :

    Element Percent Atomic Mass Relative Number of Moles Simple Ratio
    C 40 12 \[\frac{40}{12}=3.3\] \[\frac{3.3}{3.3}=1\]
    H 13.3 1 \[\frac{13.3}{1}=13.3\] \[\frac{13.3}{3.3}=4.0\]
    N 46.67 14 \[\frac{46.67}{14}=3.3\] \[\frac{3.3}{3.3}=1\]
    Empirical formula\[={{C}_{1}}{{H}_{4}}{{N}_{1}}\] Hence, the correct option is [a].


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