NEET Sample Paper NEET Sample Test Paper-19

  • question_answer Two concentric spheres of radii R and r have similar charges with equal surface densities \[(\sigma ).\]What is the electric potential at their common center?

    A) \[\frac{\sigma }{{{\varepsilon }_{0}}}\]                              

    B) \[\frac{\sigma }{{{\varepsilon }_{0}}}(R-r)\]

    C)  \[\frac{\sigma }{{{\varepsilon }_{0}}}(R+r)\]                    

    D)  None of the above. 

    Correct Answer: C

    Solution :

    Let Q and q be the charges on the spheres. The potential at the common center will be \[V=\frac{1}{4\pi {{\varepsilon }_{0}}}\times \frac{Q}{R}+\frac{1}{4\pi {{\varepsilon }_{0}}}\times \frac{q}{r}\] \[=\frac{1}{{{\varepsilon }_{0}}}\left[ \frac{Q}{4\pi {{R}^{2}}}\times R+\frac{q}{4\pi {{r}^{2}}}\times r \right]\] But \[\frac{Q}{4\pi {{R}^{2}}}=\frac{q}{4\pi {{R}^{2}}}=\sigma \] \[\therefore \]\[V=\frac{1}{{{\varepsilon }_{0}}}[\sigma R+\sigma r]=\frac{\sigma }{{{\varepsilon }_{0}}}(R+r)\] Hence, the correction option is [c].


You need to login to perform this action.
You will be redirected in 3 sec spinner