• # question_answer The diagram shows a venturimeter through which water is flowing. The speed of water at X is$2\,cm/{{s}^{-1}}.$. The speed of water at Y (taking$g=1000\,cm/{{s}^{-2}}$) is: A) $23\,cm/{{s}^{-1}}$                      B) $32\,cm/{{s}^{-1}}$C) $101\,cm/{{s}^{-1}}$                    D) $1024\,cm/{{s}^{-1}}$

Applying Bernoulli's theorem: ${{p}_{1}}+\frac{1}{2}\rho v_{1}^{2}={{P}_{2}}+\frac{1}{2}\rho v_{2}^{2}$or $\frac{1}{2}\rho (v_{2}^{2}-v_{1}^{2})={{P}_{1}}-{{P}_{2}}$ or $\frac{1}{2}\times 1(v_{2}^{2}-4)=0.51\times 1\times 1000$$[\because \,{{P}_{1}}-{{P}_{2}}=h\rho g]$ or $v_{2}^{2}-4=510\times 2=1020$or ${{v}_{2}}=32\,cm/s.$ Hence, the correction option is [b].