A) \[23\,cm/{{s}^{-1}}\]
B) \[32\,cm/{{s}^{-1}}\]
C) \[101\,cm/{{s}^{-1}}\]
D) \[1024\,cm/{{s}^{-1}}\]
Correct Answer: B
Solution :
Applying Bernoulli's theorem: \[{{p}_{1}}+\frac{1}{2}\rho v_{1}^{2}={{P}_{2}}+\frac{1}{2}\rho v_{2}^{2}\]or \[\frac{1}{2}\rho (v_{2}^{2}-v_{1}^{2})={{P}_{1}}-{{P}_{2}}\] or \[\frac{1}{2}\times 1(v_{2}^{2}-4)=0.51\times 1\times 1000\]\[[\because \,{{P}_{1}}-{{P}_{2}}=h\rho g]\] or \[v_{2}^{2}-4=510\times 2=1020\]or \[{{v}_{2}}=32\,cm/s.\] Hence, the correction option is [b].
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