• # question_answer In the circuit shown in the figure. The effective capacitance between A and B is: A) $3\,\mu F$                 B) $2\,\mu F$ C) $4\,\mu F$                 D) $8\,\mu F$

Solution :

Hence, the figure. $2\mu F$and $2\mu F$capacitors are in parallel. ${{C}_{p}}=2+2=4\mu F.$ Now the two pairs of $4\mu F$capacitors are in series. $\therefore$${{C}_{{{s}_{1}}}}=2\mu F;$ ${{C}_{{{s}_{2}}}}=2\mu F$ Across A, B the two pairs are in parallel. $\therefore$${{C}_{p}}=2+2=4\mu F.$ Hence, the correction option is [c].

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