• question_answer 70 calories of heat is required to raise the temperature of 2 moles of an ideal gas at constant pressure from $40{}^\circ C$ to $45{}^\circ C$ (R = 2$cal/mol{{\,}^{-0}}C$). The gas may be A) ${{H}_{2}}$                           B) $He$C) $C{{O}_{2}}$                        D) $N{{H}_{3}}$

$dQ=n{{C}_{P}}dT$or ${{C}_{P}}=\frac{dQ}{ndT}=\frac{70}{ndT}=\frac{70}{2.5}=\frac{7}{2}(R)$ i.e., the gas is diatomic or it is${{H}_{2}}$ Hence, the correction option is [a].