• # question_answer A gas is compressed at a constant pressure of $50\text{ }N/{{m}^{2}}$ from volume of 10 m3 to a volume of $4\text{ }{{m}^{3}}.$ Energy of 100 J is then added to the gas by heating. Its internal energy is A)  increased by 400 JB)  increased by 200 JC)  increased by 100 JD)  decreased by 200 J

Work done $=P\Delta V\,\therefore \,dW=50\times (4-10)$$=-300\,J$ Now, $dQ=dU+dW\ \therefore \,dU=100+300=400\,J$ Hence, the correction option is [a].