A) \[~6\text{ }m{{s}^{-1}}\]
B) \[~8\text{ }m{{s}^{-1}}\]
C) \[10\text{ }m{{s}^{-1}}\]
D) \[~14\text{ }m{{s}^{-1}}\]
Correct Answer: C
Solution :
\[X=6t\]and \[y=8t-5{{t}^{2}}\] \[\frac{dx}{dt}={{v}_{x}}=6\] \[\frac{dv}{dt}={{v}_{y}}=8-10t,\]\[\therefore \]\[{{\left. \frac{dy}{dt} \right|}_{t=0}}=8\] \[\therefore \]\[v=\sqrt{{{v}_{x}}+v_{y}^{2}}=\sqrt{{{6}^{2}}+{{8}^{2}}}=10\,m/s\] Hence, the correction option is [c].
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