NEET Sample Paper NEET Sample Test Paper-19

  • question_answer Two uniform strings A and B made of steel an made to vibrate under the same tension. If the firs overtone of A is equal to the second overtone of I. and if the radius of A is twice that of B, the ratio of the lengths of the strings is:

    A)  2:1                             

    B)  3:2

    C)  3:4                             

    D) 1:3

    Correct Answer: D

    Solution :

    According to question\[2{{n}_{1}}=3{{n}_{2}}\] or \[\frac{2}{2{{\ell }_{1}}}\sqrt{\frac{T}{{{m}_{1}}}}=\frac{3}{2{{\ell }_{1}}}\sqrt{\frac{T}{{{m}_{2}}}}\] or \[\frac{{{\ell }_{1}}}{{{\ell }_{2}}}=\frac{2}{3}\sqrt{\frac{{{m}_{2}}}{{{m}_{1}}}}=\frac{2}{3}\sqrt{\frac{{{V}_{2}}\rho {{\ell }_{2}}}{{{V}_{1}}\rho {{\ell }_{1}}}}\] or \[\frac{{{\ell }_{1}}}{{{\ell }_{2}}}=\frac{2}{3}\sqrt{\frac{r_{1}^{2}}{r_{1}^{2}}}=\frac{2}{3}\sqrt{{{\left( \frac{1}{2} \right)}^{2}}}\]or \[\frac{{{\ell }_{1}}}{{{\ell }_{2}}}=\frac{1}{3}\] Hence, the correction option is [d].

adversite



LIMITED OFFER HURRY UP! OFFER AVAILABLE ON ALL MATERIAL TILL TODAY ONLY!

You need to login to perform this action.
You will be redirected in 3 sec spinner

Free
Videos