NEET Sample Paper NEET Sample Test Paper-19

  • question_answer
    A ball is projected horizontally from the top  of a tower with a velocity of \[4\text{ }m{{s}^{-1}}.\] The velocity of I the ball after\[0.7\text{ }s\,(g=10\,m{{s}^{-2}})\]                 

    A) \[11\text{ }m{{s}^{-1}}\]                

    B) \[~10\text{ }m{{s}^{-1}}\]

    C) \[~8\text{ }m{{s}^{-1}}\]             

    D) \[~3\text{ }m{{s}^{-1}}\]

    Correct Answer: C

    Solution :

    Velocity of the ball after time t \[=\sqrt{v_{x}^{2}+v_{y}^{2}}=\sqrt{{{(4)}^{2}}+{{(gt)}^{2}}}\] \[=\sqrt{16+{{(10\times 0.7)}^{2}}}=8m{{s}^{-1}}\] Hence, the correction option is [c].


You need to login to perform this action.
You will be redirected in 3 sec spinner