• question_answer In the circuit shown in the figure A)  The current through NP is 0.5 AB)  The value of ${{R}_{1}}=20\Omega$C)  The value of $R=14\Omega$D)  The potential difference across R = 49 V

Potential difference across MP = p. d. across NO = p. d. across N.P (see figure.) $\therefore$${{I}_{NP}}\times 10=20\times 1$or ${{I}_{NP}}=2A$ Across MP. 0.5${{R}_{1}}=20$ or${{R}_{1}}=40\Omega$ Total current $=2+035+1.0=3.5\,A$ $3.5=\frac{69}{R+40/7}$yields $R=14\Omega$ Hence, the correct choice is [c].