A) \[Xe{{F}_{3}}\]
B) \[Xe{{F}_{4}}\]
C) \[Xe{{F}_{6}}\]
D) \[Xe{{F}_{2}}\]
Correct Answer: B
Solution :
In\[Xe{{F}_{4}},\]the four fluorine atoms are present at the corners of a square plane and two lone pairs are present at axial positions. All the individual bond moments in such an arrangement gets ruled out, as a result, the molecule has zero dipole moment. Hence, the correct option is [b].
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