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NEET Sample Paper NEET Sample Test Paper-18

Which of the following represents the arrangement in increasing order of bonds and bond dissociation energy?

A) \[O_{2}^{2-}<O_{2}^{-}<{{O}_{2}}<O_{2}^{+}\]

B) \[O_{2}^{+}<O_{2}^{2-}<O_{2}^{-}<{{O}_{2}}\]

C) \[O_{2}^{2-}<O_{2}^{-}<O_{2}^{+}<{{O}_{2}}\]

D) \[{{O}_{2}}<O_{2}^{+}<O_{2}^{2-}<O_{2}^{-}\]

Correct Answer: A

Solution :

This can be explained by the given table.

Species	Configuration	Bond order
\[{{O}_{2}}\]	\[KK\sigma {{(2s)}^{2}}{{\sigma }^{}}(2{{s}^{2}})\]\[\sigma {{(2{{p}_{z}})}^{2}}\pi {{(2{{p}_{x}})}^{2}}\pi {{(2{{p}_{y}})}^{2}}{{\pi }^{}}\]\[(2{{p}_{x}})\]\[{{\pi }^{*}}{{(2{{p}_{y}})}^{1}}\]	\[\frac{(8-4)}{2}=2\]
\[{{O}_{2}}^{+}\]	\[KK\sigma {{(2s)}^{2}}{{\sigma }^{}}{{(2s)}^{2}}\] \[\sigma {{(2{{p}_{z}})}^{2}}\pi {{(2{{p}_{x}})}^{2}}\pi {{(2{{p}_{y}})}^{2}}\] \[{{\pi }^{}}{{(2{{p}_{x}})}^{1}}\]	\[\frac{(8-3)}{2}=2.5\]
\[{{O}_{2}}^{-}\]	\[KK\,\sigma {{(2s)}^{2}}{{\sigma }^{}}{{(2s)}^{2}}\sigma (2{{p}_{z}})\] \[^{2}\pi {{(2{{p}_{x}})}^{2}}\pi {{(2{{p}_{y}})}^{2}}\]\[{{\pi }^{}}{{(2{{p}_{x}})}^{2}}{{\pi }^{*}}\]\[{{(2{{p}_{y}})}^{1}}\]	\[\frac{(8-5)}{2}=1.5\]
\[{{O}_{2}}^{2-}\]	\[KK\,\sigma {{(2s)}^{2}}{{\sigma }^{}}{{(2s)}^{2}}\sigma (2{{p}_{z}})\]\[^{2}\pi {{(2{{p}_{x}})}^{2}}\pi {{(2{{p}_{y}})}^{2}}\]\[{{\pi }^{}}{{(2{{p}_{x}})}^{2}}{{\pi }^{*}}\]\[{{(2{{p}_{y}})}^{2}}\]	\[\frac{8-6}{2}=1.0\]

So, from the given table, the order of bond dissociation energy and bond order is given as \[O_{2}^{2-}<O_{2}^{-}<{{O}_{2}}<O_{2}^{+}\] Hence, the correct option is [a].

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